(3-4i)(3+4i)=0

Solution for (3-4i)(3+4i)=0 equation:

Simplifying
(3 + -4i)(3 + 4i) = 0

Multiply (3 + -4i) * (3 + 4i)
(3(3 + 4i) + -4i * (3 + 4i)) = 0
((3 * 3 + 4i * 3) + -4i * (3 + 4i)) = 0
((9 + 12i) + -4i * (3 + 4i)) = 0
(9 + 12i + (3 * -4i + 4i * -4i)) = 0
(9 + 12i + (-12i + -16i2)) = 0

Combine like terms: 12i + -12i = 0
(9 + 0 + -16i2) = 0
(9 + -16i2) = 0

Solving
9 + -16i2 = 0

Solving for variable 'i'.

Move all terms containing i to the left, all other terms to the right.

Add '-9' to each side of the equation.
9 + -9 + -16i2 = 0 + -9

Combine like terms: 9 + -9 = 0
0 + -16i2 = 0 + -9
-16i2 = 0 + -9

Combine like terms: 0 + -9 = -9
-16i2 = -9

Divide each side by '-16'.
i2 = 0.5625

Simplifying
i2 = 0.5625

Take the square root of each side:
i = {-0.75, 0.75}