(3-4i)(5-2i)=0

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Solution for (3-4i)(5-2i)=0 equation:


Simplifying
(3 + -4i)(5 + -2i) = 0

Multiply (3 + -4i) * (5 + -2i)
(3(5 + -2i) + -4i * (5 + -2i)) = 0
((5 * 3 + -2i * 3) + -4i * (5 + -2i)) = 0
((15 + -6i) + -4i * (5 + -2i)) = 0
(15 + -6i + (5 * -4i + -2i * -4i)) = 0
(15 + -6i + (-20i + 8i2)) = 0

Combine like terms: -6i + -20i = -26i
(15 + -26i + 8i2) = 0

Solving
15 + -26i + 8i2 = 0

Solving for variable 'i'.

Factor a trinomial.
(3 + -4i)(5 + -2i) = 0

Subproblem 1

Set the factor '(3 + -4i)' equal to zero and attempt to solve: Simplifying 3 + -4i = 0 Solving 3 + -4i = 0 Move all terms containing i to the left, all other terms to the right. Add '-3' to each side of the equation. 3 + -3 + -4i = 0 + -3 Combine like terms: 3 + -3 = 0 0 + -4i = 0 + -3 -4i = 0 + -3 Combine like terms: 0 + -3 = -3 -4i = -3 Divide each side by '-4'. i = 0.75 Simplifying i = 0.75

Subproblem 2

Set the factor '(5 + -2i)' equal to zero and attempt to solve: Simplifying 5 + -2i = 0 Solving 5 + -2i = 0 Move all terms containing i to the left, all other terms to the right. Add '-5' to each side of the equation. 5 + -5 + -2i = 0 + -5 Combine like terms: 5 + -5 = 0 0 + -2i = 0 + -5 -2i = 0 + -5 Combine like terms: 0 + -5 = -5 -2i = -5 Divide each side by '-2'. i = 2.5 Simplifying i = 2.5

Solution

i = {0.75, 2.5}

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