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D( i )
5-(3*i) = 0
5-(3*i) = 0
5-(3*i) = 0
5-3*i = 0
5-3*i = 0 // - 5
-3*i = -5 // : -3
i = -5/(-3)
i = 5/3
i in (-oo:5/3) U (5/3:+oo)
(3-(5*i))/(5-(3*i)) = 0
(3-5*i)/(5-3*i) = 0
3-5*i = 0 // - 3
-5*i = -3 // : -5
i = -3/(-5)
i = 3/5
i = 3/5
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