(3-7i)(3+7i)=0

Solution for (3-7i)(3+7i)=0 equation:

(3-7i)(3+7i)=0

We add all the numbers together, and all the variables

(-7i+3)(7i+3)=0

We multiply parentheses ..

(-49i^2-21i+21i+9)=0

We get rid of parentheses

-49i^2-21i+21i+9=0

We add all the numbers together, and all the variables

-49i^2+9=0

a = -49; b = 0; c = +9;
Δ = b2-4ac
Δ = 02-4·(-49)·9
Δ = 1764
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$i_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$i_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1764}=42$
$i_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-42}{2*-49}=\frac{-42}{-98}
=3/7
$
$i_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+42}{2*-49}=\frac{42}{-98}
=-3/7
$