(3-7y/3y)-(1-3y/2y)=1

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Solution for (3-7y/3y)-(1-3y/2y)=1 equation: 


y in (-oo:+oo)

((3*y)/2)*y-(((7*y)/3)*y)-1+3 = 1 // - 1

((3*y)/2)*y-(((7*y)/3)*y)-1-1+3 = 0

(-7/3)*y^2+((3*y)/2)*y-1-1+3 = 0

-5/6*y^2 = -1 // : -5/6

y^2 = 6/5

y^2 = 6/5 // ^ 1/2

abs(y) = (6/5)^(1/2)

y = (6/5)^(1/2) or y = -(6/5)^(1/2)

y in { (6/5)^(1/2), -(6/5)^(1/2) }

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