(3-8x)(8x-1)=0

Solution for (3-8x)(8x-1)=0 equation:

(3-8x)(8x-1)=0

We add all the numbers together, and all the variables

(-8x+3)(8x-1)=0

We multiply parentheses ..

(-64x^2+8x+24x-3)=0

We get rid of parentheses

-64x^2+8x+24x-3=0

We add all the numbers together, and all the variables

-64x^2+32x-3=0

a = -64; b = 32; c = -3;
Δ = b2-4ac
Δ = 322-4·(-64)·(-3)
Δ = 256
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{256}=16$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(32)-16}{2*-64}=\frac{-48}{-128}
=3/8
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(32)+16}{2*-64}=\frac{-16}{-128}
=1/8
$