(3-9i)(-3+9i)=0

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Solution for (3-9i)(-3+9i)=0 equation: 



(3-9i)(-3+9i)=0

We add all the numbers together, and all the variables

(-9i+3)(9i-3)=0

We multiply parentheses ..

(-81i^2+27i+27i-9)=0

We get rid of parentheses

-81i^2+27i+27i-9=0

We add all the numbers together, and all the variables

-81i^2+54i-9=0

a = -81; b = 54; c = -9;
Δ = b2-4ac
Δ = 542-4·(-81)·(-9)
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$i=\frac{-b}{2a}=\frac{-54}{-162}=1/3$

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