(3-9y)y=0

Solution for (3-9y)y=0 equation:

(3-9y)y=0

We add all the numbers together, and all the variables

(-9y+3)y=0

We multiply parentheses

-9y^2+3y=0

a = -9; b = 3; c = 0;
Δ = b2-4ac
Δ = 32-4·(-9)·0
Δ = 9
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{9}=3$
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(3)-3}{2*-9}=\frac{-6}{-18}
=1/3
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(3)+3}{2*-9}=\frac{0}{-18}
=0
$