(3-c)(c-3)=

Solution for (3-c)(c-3)= equation:

Simplifying
(3 + -1c)(c + -3) = 0

Reorder the terms:
(3 + -1c)(-3 + c) = 0

Multiply (3 + -1c) * (-3 + c)
(3(-3 + c) + -1c * (-3 + c)) = 0
((-3 * 3 + c * 3) + -1c * (-3 + c)) = 0
((-9 + 3c) + -1c * (-3 + c)) = 0
(-9 + 3c + (-3 * -1c + c * -1c)) = 0
(-9 + 3c + (3c + -1c2)) = 0

Combine like terms: 3c + 3c = 6c
(-9 + 6c + -1c2) = 0

Solving
-9 + 6c + -1c2 = 0

Solving for variable 'c'.

Factor a trinomial.
(-3 + c)(3 + -1c) = 0

Subproblem 1
Set the factor '(-3 + c)' equal to zero and attempt to solve:

Simplifying
-3 + c = 0

Solving
-3 + c = 0

Move all terms containing c to the left, all other terms to the right.

Add '3' to each side of the equation.
-3 + 3 + c = 0 + 3

Combine like terms: -3 + 3 = 0
0 + c = 0 + 3
c = 0 + 3

Combine like terms: 0 + 3 = 3
c = 3

Simplifying
c = 3
Subproblem 2
Set the factor '(3 + -1c)' equal to zero and attempt to solve:

Simplifying
3 + -1c = 0

Solving
3 + -1c = 0

Move all terms containing c to the left, all other terms to the right.

Add '-3' to each side of the equation.
3 + -3 + -1c = 0 + -3

Combine like terms: 3 + -3 = 0
0 + -1c = 0 + -3
-1c = 0 + -3

Combine like terms: 0 + -3 = -3
-1c = -3

Divide each side by '-1'.
c = 3

Simplifying
c = 3
Solution
c = {3, 3}