(3-i)-(4+3i)+(1-2i)=

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Solution for (3-i)-(4+3i)+(1-2i)= equation:


Simplifying
(3 + -1i) + -1(4 + 3i) + (1 + -2i) = 0

Remove parenthesis around (3 + -1i)
3 + -1i + -1(4 + 3i) + (1 + -2i) = 0
3 + -1i + (4 * -1 + 3i * -1) + (1 + -2i) = 0
3 + -1i + (-4 + -3i) + (1 + -2i) = 0

Remove parenthesis around (1 + -2i)
3 + -1i + -4 + -3i + 1 + -2i = 0

Reorder the terms:
3 + -4 + 1 + -1i + -3i + -2i = 0

Combine like terms: 3 + -4 = -1
-1 + 1 + -1i + -3i + -2i = 0

Combine like terms: -1 + 1 = 0
0 + -1i + -3i + -2i = 0
-1i + -3i + -2i = 0

Combine like terms: -1i + -3i = -4i
-4i + -2i = 0

Combine like terms: -4i + -2i = -6i
-6i = 0

Solving
-6i = 0

Solving for variable 'i'.

Move all terms containing i to the left, all other terms to the right.

Divide each side by '-6'.
i = 0

Simplifying
i = 0

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