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(3-v)(3v-5)=0
We add all the numbers together, and all the variables
(-1v+3)(3v-5)=0
We multiply parentheses ..
(-3v^2+5v+9v-15)=0
We get rid of parentheses
-3v^2+5v+9v-15=0
We add all the numbers together, and all the variables
-3v^2+14v-15=0
a = -3; b = 14; c = -15;
Δ = b2-4ac
Δ = 142-4·(-3)·(-15)
Δ = 16
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{16}=4$$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(14)-4}{2*-3}=\frac{-18}{-6} =+3 $$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(14)+4}{2*-3}=\frac{-10}{-6} =1+2/3 $
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