(3-x)(4x-2)=-2x(2x+9)

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Solution for (3-x)(4x-2)=-2x(2x+9) equation: 



(3-x)(4x-2)=-2x(2x+9)

We move all terms to the left:

(3-x)(4x-2)-(-2x(2x+9))=0

We add all the numbers together, and all the variables

(-1x+3)(4x-2)-(-2x(2x+9))=0

We multiply parentheses ..

(-4x^2+2x+12x-6)-(-2x(2x+9))=0



We calculate terms in parentheses: -(-2x(2x+9)), so:

-2x(2x+9)

We multiply parentheses

-4x^2-18x

Back to the equation:

-(-4x^2-18x)



We get rid of parentheses

-4x^2+4x^2+2x+12x+18x-6=0

We add all the numbers together, and all the variables

32x-6=0

We move all terms containing x to the left, all other terms to the right

32x=6

x=6/32

x=3/16

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