(3-x)(5x+8)=0

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Solution for (3-x)(5x+8)=0 equation:



(3-x)(5x+8)=0
We add all the numbers together, and all the variables
(-1x+3)(5x+8)=0
We multiply parentheses ..
(-5x^2-8x+15x+24)=0
We get rid of parentheses
-5x^2-8x+15x+24=0
We add all the numbers together, and all the variables
-5x^2+7x+24=0
a = -5; b = 7; c = +24;
Δ = b2-4ac
Δ = 72-4·(-5)·24
Δ = 529
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{529}=23$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(7)-23}{2*-5}=\frac{-30}{-10} =+3 $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(7)+23}{2*-5}=\frac{16}{-10} =-1+3/5 $

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