(3-x)+(1-x)+(2-x)+(6-x)=0

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Solution for (3-x)+(1-x)+(2-x)+(6-x)=0 equation:


Simplifying
(3 + -1x) + (1 + -1x) + (2 + -1x) + (6 + -1x) = 0

Remove parenthesis around (3 + -1x)
3 + -1x + (1 + -1x) + (2 + -1x) + (6 + -1x) = 0

Remove parenthesis around (1 + -1x)
3 + -1x + 1 + -1x + (2 + -1x) + (6 + -1x) = 0

Remove parenthesis around (2 + -1x)
3 + -1x + 1 + -1x + 2 + -1x + (6 + -1x) = 0

Remove parenthesis around (6 + -1x)
3 + -1x + 1 + -1x + 2 + -1x + 6 + -1x = 0

Reorder the terms:
3 + 1 + 2 + 6 + -1x + -1x + -1x + -1x = 0

Combine like terms: 3 + 1 = 4
4 + 2 + 6 + -1x + -1x + -1x + -1x = 0

Combine like terms: 4 + 2 = 6
6 + 6 + -1x + -1x + -1x + -1x = 0

Combine like terms: 6 + 6 = 12
12 + -1x + -1x + -1x + -1x = 0

Combine like terms: -1x + -1x = -2x
12 + -2x + -1x + -1x = 0

Combine like terms: -2x + -1x = -3x
12 + -3x + -1x = 0

Combine like terms: -3x + -1x = -4x
12 + -4x = 0

Solving
12 + -4x = 0

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-12' to each side of the equation.
12 + -12 + -4x = 0 + -12

Combine like terms: 12 + -12 = 0
0 + -4x = 0 + -12
-4x = 0 + -12

Combine like terms: 0 + -12 = -12
-4x = -12

Divide each side by '-4'.
x = 3

Simplifying
x = 3

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