(3-x)+11x=41

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Solution for (3-x)+11x=41 equation:



(3-x)+11x=41
We move all terms to the left:
(3-x)+11x-(41)=0
We add all the numbers together, and all the variables
(-1x+3)+11x-41=0
We add all the numbers together, and all the variables
11x+(-1x+3)-41=0
We get rid of parentheses
11x-1x+3-41=0
We add all the numbers together, and all the variables
10x-38=0
We move all terms containing x to the left, all other terms to the right
10x=38
x=38/10
x=3+4/5

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