(3-x)/6=(2-x)/4

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Solution for (3-x)/6=(2-x)/4 equation: 



(3-x)/6=(2-x)/4

We move all terms to the left:

(3-x)/6-((2-x)/4)=0

We add all the numbers together, and all the variables

(-1x+3)/6-((-1x+2)/4)=0

We calculate fractions


(-x)/()+(-((-1x+2)*6)/()=0



We calculate terms in parentheses: +(-((-1x+2)*6)/(), so:

-((-1x+2)*6)/(

We multiply all the terms by the denominator


-((-1x+2)*6)



We calculate terms in parentheses: -((-1x+2)*6), so:

(-1x+2)*6

We multiply parentheses

-6x+12

Back to the equation:

-(-6x+12)



We get rid of parentheses

6x-12

Back to the equation:

+(6x-12)



We add all the numbers together, and all the variables

(-1x)/()+(6x-12)=0

We get rid of parentheses

(-1x)/()+6x-12=0

We multiply all the terms by the denominator


(-1x)+6x*()-12*()=0

We add all the numbers together, and all the variables

(-1x)+6x*()=0

We get rid of parentheses

-1x+6x*()=0

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