(3-y)(4y-6)=0

Solution for (3-y)(4y-6)=0 equation:

(3-y)(4y-6)=0

We add all the numbers together, and all the variables

(-1y+3)(4y-6)=0

We multiply parentheses ..

(-4y^2+6y+12y-18)=0

We get rid of parentheses

-4y^2+6y+12y-18=0

We add all the numbers together, and all the variables

-4y^2+18y-18=0

a = -4; b = 18; c = -18;
Δ = b2-4ac
Δ = 182-4·(-4)·(-18)
Δ = 36
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{36}=6$
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(18)-6}{2*-4}=\frac{-24}{-8}
=+3
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(18)+6}{2*-4}=\frac{-12}{-8}
=1+1/2
$