(3.2-x)(3.6-x)=0

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Solution for (3.2-x)(3.6-x)=0 equation:



(3.2-x)(3.6-x)=0
We add all the numbers together, and all the variables
(-1x+3.2)(-1x+3.6)=0
We multiply parentheses ..
(+x^2-3.6x-3.2x+11.52)=0
We get rid of parentheses
x^2-3.6x-3.2x+11.52=0
We add all the numbers together, and all the variables
x^2-6.8x+11.52=0
a = 1; b = -6.8; c = +11.52;
Δ = b2-4ac
Δ = -6.82-4·1·11.52
Δ = 0.16
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-6.8)-\sqrt{0.16}}{2*1}=\frac{6.8-\sqrt{0.16}}{2} $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-6.8)+\sqrt{0.16}}{2*1}=\frac{6.8+\sqrt{0.16}}{2} $

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