(3.5x)(2x)+x=1080

Solution for (3.5x)(2x)+x=1080 equation:

(3.5x)(2x)+x=1080

We move all terms to the left:

(3.5x)(2x)+x-(1080)=0

We add all the numbers together, and all the variables

(+3.5x)2x+x-1080=0

We add all the numbers together, and all the variables

x+(+3.5x)2x-1080=0

We multiply parentheses

6x^2+x-1080=0

a = 6; b = 1; c = -1080;
Δ = b2-4ac
Δ = 12-4·6·(-1080)
Δ = 25921
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{25921}=161$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-161}{2*6}=\frac{-162}{12}
=-13+1/2
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+161}{2*6}=\frac{160}{12}
=13+1/3
$