(3.5x)+(3x-5)=(x+35)+(4x-10)

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Solution for (3.5x)+(3x-5)=(x+35)+(4x-10) equation: 



(3.5x)+(3x-5)=(x+35)+(4x-10)

We move all terms to the left:

(3.5x)+(3x-5)-((x+35)+(4x-10))=0

We add all the numbers together, and all the variables

(+3.5x)+(3x-5)-((x+35)+(4x-10))=0

We get rid of parentheses

3.5x+3x-((x+35)+(4x-10))-5=0



We calculate terms in parentheses: -((x+35)+(4x-10)), so:

(x+35)+(4x-10)

We get rid of parentheses

x+4x+35-10

We add all the numbers together, and all the variables

5x+25

Back to the equation:

-(5x+25)



We add all the numbers together, and all the variables

6.5x-(5x+25)-5=0

We get rid of parentheses

6.5x-5x-25-5=0

We add all the numbers together, and all the variables

1.5x-30=0

We move all terms containing x to the left, all other terms to the right

1.5x=30

x=30/1.5

x=20

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