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(3.6/2)x=1.8(6x+1)
We move all terms to the left:
(3.6/2)x-(1.8(6x+1))=0
Domain of the equation: 2)x!=0We add all the numbers together, and all the variables
x!=0/1
x!=0
x∈R
(+3.6/2)x-(1.8(6x+1))=0
We multiply parentheses
3x^2-(1.8(6x+1))=0
We calculate terms in parentheses: -(1.8(6x+1)), so:We get rid of parentheses
1.8(6x+1)
We multiply parentheses
10.8x+1.8
Back to the equation:
-(10.8x+1.8)
3x^2-10.8x-1.8=0
a = 3; b = -10.8; c = -1.8;
Δ = b2-4ac
Δ = -10.82-4·3·(-1.8)
Δ = 138.24
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-10.8)-\sqrt{138.24}}{2*3}=\frac{10.8-\sqrt{138.24}}{6} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-10.8)+\sqrt{138.24}}{2*3}=\frac{10.8+\sqrt{138.24}}{6} $
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