(3.7x-5)(3.7x-5)=13.4

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Solution for (3.7x-5)(3.7x-5)=13.4 equation:



(3.7x-5)(3.7x-5)=13.4
We move all terms to the left:
(3.7x-5)(3.7x-5)-(13.4)=0
We add all the numbers together, and all the variables
(3.7x-5)(3.7x-5)-13.4=0
We multiply parentheses ..
(+9x^2-15x-15x+25)-13.4=0
We get rid of parentheses
9x^2-15x-15x+25-13.4=0
We add all the numbers together, and all the variables
9x^2-30x+11.6=0
a = 9; b = -30; c = +11.6;
Δ = b2-4ac
Δ = -302-4·9·11.6
Δ = 482.4
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-30)-\sqrt{482.4}}{2*9}=\frac{30-\sqrt{482.4}}{18} $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-30)+\sqrt{482.4}}{2*9}=\frac{30+\sqrt{482.4}}{18} $

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