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(3/(2x-1))+(4/(x+2))=2
We move all terms to the left:
(3/(2x-1))+(4/(x+2))-(2)=0
Domain of the equation: (2x-1))!=0
x∈R
Domain of the equation: (x+2))!=0We calculate fractions
x∈R
(3x+6)/((2x-1))*x+(8x-4)/((2x-1))*x-2=0
We multiply all the terms by the denominator
(3x+6)+(8x-4)-2*((2x-1))*x=0
We get rid of parentheses
3x+8x-2*((2x-1))*x+6-4=0
We add all the numbers together, and all the variables
11x-2*((2x-1))*x+2=0
We move all terms containing x to the left, all other terms to the right
11x-2*((2x-1))*x=-2
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