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(3/(4+t))+8=40
We move all terms to the left:
(3/(4+t))+8-(40)=0
Domain of the equation: (4+t))!=0We add all the numbers together, and all the variables
We move all terms containing t to the left, all other terms to the right
t)!=-4
t!=-4/1
t!=-4
t∈R
(3/(t+4))+8-40=0
We add all the numbers together, and all the variables
(3/(t+4))-32=0
We multiply all the terms by the denominator
(3-32*(t+4))=0
We calculate terms in parentheses: +(3-32*(t+4)), so:We get rid of parentheses
3-32*(t+4)
determiningTheFunctionDomain -32*(t+4)+3
We multiply parentheses
-32t-128+3
We add all the numbers together, and all the variables
-32t-125
Back to the equation:
+(-32t-125)
-32t-125=0
We move all terms containing t to the left, all other terms to the right
-32t=125
t=125/-32
t=-3+29/32
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