(3/(m-4))+(1/(3(m-4)))=6/m

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Solution for (3/(m-4))+(1/(3(m-4)))=6/m equation: 



(3/(m-4))+(1/(3(m-4)))=6/m

We move all terms to the left:

(3/(m-4))+(1/(3(m-4)))-(6/m)=0



Domain of the equation: (m-4))!=0

m∈R





Domain of the equation: (3(m-4)))!=0

m∈R





Domain of the equation: m)!=0

m!=0/1

m!=0

m∈R



We add all the numbers together, and all the variables

(3/(m-4))+(1/(3(m-4)))-(+6/m)=0

We get rid of parentheses

(3/(m-4))+(1/(3(m-4)))-6/m=0

We calculate fractions


((3*(3(m-4)))*m)/((m-4))*(3(m-4)))*m)+((1*(m-4))*m)/((m-4))*(3(m-4)))*m)+(-6*(m-4))*(3(m-4))))/((m-4))*(3(m-4)))*m)=0

We can not solve this equation

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