(3/(x+4))-7=(-4/(x+4))

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Solution for (3/(x+4))-7=(-4/(x+4)) equation: 


D( x )

x+4 = 0

x+4 = 0

x+4 = 0

x+4 = 0 // - 4

x = -4

x in (-oo:-4) U (-4:+oo)

3/(x+4)-7 = -4/(x+4) // + -4/(x+4)

3/(x+4)-(-4/(x+4))-7 = 0

3/(x+4)+4*(x+4)^-1-7 = 0

3/(x+4)+4/(x+4)-7 = 0

3/(x+4)+4/(x+4)+(-7*(x+4))/(x+4) = 0

3-7*(x+4)+4 = 0

7-7*x-28 = 0

-7*x-21 = 0

(-7*x-21)/(x+4) = 0

(-7*x-21)/(x+4) = 0 // * x+4

-7*x-21 = 0

-7*x-21 = 0 // + 21

-7*x = 21 // : -7

x = 21/(-7)

x = -3

x = -3

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