(3/(x-2))+(4/5)=27/(5(x-2))

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Solution for (3/(x-2))+(4/5)=27/(5(x-2)) equation: 



(3/(x-2))+(4/5)=27/(5(x-2))

We move all terms to the left:

(3/(x-2))+(4/5)-(27/(5(x-2)))=0



Domain of the equation: (x-2))!=0

x∈R





Domain of the equation: (5(x-2)))!=0

x∈R



We add all the numbers together, and all the variables

(3/(x-2))-(27/(5(x-2)))+(+4/5)=0

We get rid of parentheses

(3/(x-2))-(27/(5(x-2)))+4/5=0

We calculate fractions


((3*(5(x-2)))*5)/((x-2))*(5(x-2)))*5)+(-(27*(x-2))*5)/((x-2))*(5(x-2)))*5)+(4*(x-2))*(5(x-2))))/((x-2))*(5(x-2)))*5)=0

We can not solve this equation

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