(3/(x-5))=((-2/(x+1)))+((3/(x-5)(x+1)))

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Solution for (3/(x-5))=((-2/(x+1)))+((3/(x-5)(x+1))) equation:


D( x )

x-5 = 0

x+1 = 0

x-5 = 0

x-5 = 0

x-5 = 0 // + 5

x = 5

x+1 = 0

x+1 = 0

x+1 = 0 // - 1

x = -1

x in (-oo:-1) U (-1:5) U (5:+oo)

3/(x-5) = (3/(x-5))*(x+1)-2/(x+1) // - (3/(x-5))*(x+1)-2/(x+1)

3/(x-5)-(-2/(x+1))-((3/(x-5))*(x+1)) = 0

3/(x-5)+2*(x+1)^-1-3*(x+1)*(x-5)^-1 = 0

3/(x-5)+2/(x+1)+(-3*(x+1))/(x-5) = 0

(3*(x+1))/((x-5)*(x+1))+(2*(x-5))/((x-5)*(x+1))+(-3*(x+1)^2)/((x-5)*(x+1)) = 0

3*(x+1)+2*(x-5)-3*(x+1)^2 = 0

5*x-3*x^2-6*x-7-3 = 0

-3*x^2-x-10 = 0

-3*x^2-x-10 = 0

-1*(3*x^2+x+10) = 0

3*x^2+x+10 = 0

DELTA = 1^2-(3*4*10)

DELTA = -119

DELTA < 0

-1 = 0

-1/((x-5)*(x+1)) = 0

-1/((x-5)*(x+1)) = 0 // * (x-5)*(x+1)

-1 = 0

x belongs to the empty set

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