(3/1)x+4=(4x-1)/5

Solution for (3/1)x+4=(4x-1)/5 equation:

(3/1)x+4=(4x-1)/5

We move all terms to the left:

(3/1)x+4-((4x-1)/5)=0


Domain of the equation: 1)x!=0

x!=0/1

x!=0

x∈R


We add all the numbers together, and all the variables

0x-((4x-1)/5)+4=0

We add all the numbers together, and all the variables

x-((4x-1)/5)+4=0

We multiply all the terms by the denominator


x*5)-((4x-1)+4*5)=0

We add all the numbers together, and all the variables

x*5)-((4x-1)=0

Wy multiply elements

5x^2=0

a = 5; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·5·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{0}{10}=0$