(3/10)(x+2)=12

Solution for (3/10)(x+2)=12 equation:

(3/10)(x+2)=12

We move all terms to the left:

(3/10)(x+2)-(12)=0


Domain of the equation: 10)(x+2)!=0

x∈R


We add all the numbers together, and all the variables

(+3/10)(x+2)-12=0

We multiply parentheses ..

(+3x^2+3/10*2)-12=0

We multiply all the terms by the denominator


(+3x^2+3-12*10*2)=0

We get rid of parentheses

3x^2+3-12*10*2=0

We add all the numbers together, and all the variables

3x^2-237=0

a = 3; b = 0; c = -237;
Δ = b2-4ac
Δ = 02-4·3·(-237)
Δ = 2844
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{2844}=\sqrt{36*79}=\sqrt{36}*\sqrt{79}=6\sqrt{79}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-6\sqrt{79}}{2*3}=\frac{0-6\sqrt{79}}{6}
=-\frac{6\sqrt{79}}{6}
=-\sqrt{79}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+6\sqrt{79}}{2*3}=\frac{0+6\sqrt{79}}{6}
=\frac{6\sqrt{79}}{6}
=\sqrt{79}
$