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(3/10)a=60
We move all terms to the left:
(3/10)a-(60)=0
Domain of the equation: 10)a!=0We add all the numbers together, and all the variables
a!=0/1
a!=0
a∈R
(+3/10)a-60=0
We multiply parentheses
3a^2-60=0
a = 3; b = 0; c = -60;
Δ = b2-4ac
Δ = 02-4·3·(-60)
Δ = 720
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{720}=\sqrt{144*5}=\sqrt{144}*\sqrt{5}=12\sqrt{5}$$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-12\sqrt{5}}{2*3}=\frac{0-12\sqrt{5}}{6} =-\frac{12\sqrt{5}}{6} =-2\sqrt{5} $$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+12\sqrt{5}}{2*3}=\frac{0+12\sqrt{5}}{6} =\frac{12\sqrt{5}}{6} =2\sqrt{5} $
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