(3/2)(2x-3)-4(x-2)=12

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Solution for (3/2)(2x-3)-4(x-2)=12 equation: 


x in (-oo:+oo)

(3/2)*(2*x-3)-(4*(x-2)) = 12 // - 12

(3/2)*(2*x-3)-(4*(x-2))-12 = 0

(3/2)*(2*x-3)-4*(x-2)-12 = 0

3/2*(2*x-3)-4*(x-2)-12 = 0

3/2*(2*x-3)-4*(x-2)-12 = 0

7/2-x-12 = 0

-x-17/2 = 0

-x-17/2 = 0

-x-17/2 = 0 // + 17/2

-x = 17/2 // * -1

x = -17/2

x = -17/2

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