(3/2)(x-2)-5=19

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Solution for (3/2)(x-2)-5=19 equation: 



(3/2)(x-2)-5=19

We move all terms to the left:

(3/2)(x-2)-5-(19)=0



Domain of the equation: 2)(x-2)!=0

x∈R



We add all the numbers together, and all the variables

(+3/2)(x-2)-5-19=0

We add all the numbers together, and all the variables

(+3/2)(x-2)-24=0

We multiply parentheses ..

(+3x^2+3/2*-2)-24=0

We multiply all the terms by the denominator


(+3x^2+3-24*2*-2)=0

We get rid of parentheses

3x^2+3-2-24*2*=0

We add all the numbers together, and all the variables

3x^2=0

a = 3; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·3·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{0}{6}=0$

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