(3/2)+(1/5)=(1/x)

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Solution for (3/2)+(1/5)=(1/x) equation: 


D( x )

x = 0

x = 0

x = 0

x in (-oo:0) U (0:+oo)

3/2+1/5 = 1/x // - 1/x

3/2-(1/x)+1/5 = 0

3/2-x^-1+1/5 = 0

-1*x^-1 = -17/10 // : -1

x^-1 = 17/10

-1 < 0

1/(x^1) = 17/10 // * x^1

1 = 17/10*x^1 // : 17/10

10/17 = x^1

x = 10/17

x = 10/17

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