(3/2)+(2m/7)=(31/14)

Solution for (3/2)+(2m/7)=(31/14) equation:

(3/2)+(2m/7)=(31/14)

We move all terms to the left:

(3/2)+(2m/7)-((31/14))=0

We add all the numbers together, and all the variables

(+2m/7)+(+3/2)-((+31/14))=0

We get rid of parentheses

2m/7+3/2-((+31/14))=0

We calculate fractions


56m^2/()+()/()+()/()=0

We add all the numbers together, and all the variables

56m^2/()+2=0

We multiply all the terms by the denominator


56m^2+2*()=0

We add all the numbers together, and all the variables

56m^2=0

a = 56; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·56·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$m=\frac{-b}{2a}=\frac{0}{112}=0$