(3/2)+(4/x+1)=(x+1/x-1)

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Solution for (3/2)+(4/x+1)=(x+1/x-1) equation:


D( x )

x = 0

x = 0

x = 0

x in (-oo:0) U (0:+oo)

4/x+3/2+1 = x+1/x-1 // - x+1/x-1

4/x-x-(1/x)+3/2+1+1 = 0

4/x-x-x^-1+3/2+1+1 = 0

3*x^-1-1*x^1+7/2*x^0 = 0

(7/2*x^1-1*x^2+3*x^0)/(x^1) = 0 // * x^2

x^1*(7/2*x^1-1*x^2+3*x^0) = 0

x^1

(7/2)*x-x^2+3 = 0

(7/2)*x-x^2+3 = 0

DELTA = (7/2)^2-(-1*3*4)

DELTA = 97/4

DELTA > 0

x = ((97/4)^(1/2)-(7/2))/(-1*2) or x = (-(7/2)-(97/4)^(1/2))/(-1*2)

x = ((97/4)^(1/2)-7/2)/(-2) or x = ((97/4)^(1/2)+7/2)/2

x in { ((97/4)^(1/2)-7/2)/(-2), ((97/4)^(1/2)+7/2)/2}

x in { ((97/4)^(1/2)-7/2)/(-2), ((97/4)^(1/2)+7/2)/2 }

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