(3/2)+x+(2/5)=(x+3)/5

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Solution for (3/2)+x+(2/5)=(x+3)/5 equation: 


x in (-oo:+oo)

x+3/2+2/5 = (x+3)/5 // - (x+3)/5

x-((x+3)/5)+3/2+2/5 = 0

(-1*(x+3))/5+x+3/2+2/5 = 0

(-1*2*(x+3))/(2*5)+(2*5*x)/(2*5)+(3*5)/(2*5)+(2^2)/(2*5) = 0

2*5*x-1*2*(x+3)+3*5+4 = 0

8*x-6+4+15 = 0

8*x+4+9 = 0

8*x+13 = 0

(8*x+13)/(2*5) = 0

(8*x+13)/(2*5) = 0 // * 2*5

8*x+13 = 0

8*x+13 = 0 // - 13

8*x = -13 // : 8

x = -13/8

x = -13/8

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