(3/2)x+(6/5)=7/5x

Solution for (3/2)x+(6/5)=7/5x equation:

(3/2)x+(6/5)=7/5x

We move all terms to the left:

(3/2)x+(6/5)-(7/5x)=0


Domain of the equation: 2)x!=0

x!=0/1

x!=0

x∈R



Domain of the equation: 5x)!=0

x!=0/1

x!=0

x∈R


We add all the numbers together, and all the variables

(+3/2)x-(+7/5x)+(+6/5)=0

We multiply parentheses

3x^2-(+7/5x)+(+6/5)=0

We get rid of parentheses

3x^2-7/5x+6/5=0

We calculate fractions


3x^2=0

a = 3; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·3·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{0}{6}=0$