(3/2)x+1=(1/5)x+8

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Solution for (3/2)x+1=(1/5)x+8 equation: 



(3/2)x+1=(1/5)x+8

We move all terms to the left:

(3/2)x+1-((1/5)x+8)=0



Domain of the equation: 2)x!=0

x!=0/1

x!=0

x∈R





Domain of the equation: 5)x+8)!=0

x!=0/1

x!=0

x∈R



We add all the numbers together, and all the variables

(+3/2)x-((+1/5)x+8)+1=0

We multiply parentheses

3x^2-((+1/5)x+8)+1=0

We multiply all the terms by the denominator


3x^2*5)x+8)-((+1*5)x+8)+1=0

We add all the numbers together, and all the variables

3x^2*5)x+8)-(5x+8)+1=0

Wy multiply elements

15x^3=0

We do not support expression: x^3

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