(3/2)x-y=-3;-5x+4y=16

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2x+y=8
x+3y=14

Solution for (3/2)x-y=-3;-5x+4y=16 system of equations: 


  • /| (3/2)*x-y+3 = 0| 4*y-5*x-16 = 0
  • We try to solve the equation: (3/2)*x-y+3 = 0
  • 3/2*x-y+3 = 0 // - 3/2*x+3
  • -y = -(3/2*x+3) // * -1
  • y = 3/2*x+3
  • We insert the solution into one of the initial equations of our system of equations
  • We get a system of equations:
  • /| 4*(3/2*x+3)-5*x-16 = 0| y = 3/2*x+3
  • 4*(3/2*x+3)-5*x-16 = 0
  • x-16+12 = 0
  • x-4 = 0
  • x-4 = 0 // + 4
  • x = 4
  • We insert the solution into one of the initial equations of our system of equations
  • For y = 3/2*x+3: 
  • y = 3/2*4+3
  • y = 3+6
  • y = 9
  • We get a system of equations:
  • /| y = 9| x = 4

 

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