(3/2)y+4=1/3

Solution for (3/2)y+4=1/3 equation:

(3/2)y+4=1/3

We move all terms to the left:

(3/2)y+4-(1/3)=0


Domain of the equation: 2)y!=0

y!=0/1

y!=0

y∈R


We add all the numbers together, and all the variables

(+3/2)y+4-(+1/3)=0

We multiply parentheses

3y^2+4-(+1/3)=0

We get rid of parentheses

3y^2+4-1/3=0

We multiply all the terms by the denominator


3y^2*3-1+4*3=0

We add all the numbers together, and all the variables

3y^2*3+11=0

Wy multiply elements

9y^2+11=0

a = 9; b = 0; c = +11;
Δ = b2-4ac
Δ = 02-4·9·11
Δ = -396
Delta is less than zero, so there is no solution for the equation