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(3/2x)+(2/5)=(7/5x)
We move all terms to the left:
(3/2x)+(2/5)-((7/5x))=0
Domain of the equation: 2x)!=0
x!=0/1
x!=0
x∈R
Domain of the equation: 5x))!=0We add all the numbers together, and all the variables
x!=0/1
x!=0
x∈R
(+3/2x)-((+7/5x))+(+2/5)=0
We get rid of parentheses
3/2x-((+7/5x))+2/5=0
We calculate fractions
75x/50x^2+(-((+7*2x)/50x^2+4x/50x^2=0
We can not solve this equation
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