(3/2x+20)+(5/2x+40)=180

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Solution for (3/2x+20)+(5/2x+40)=180 equation:



(3/2x+20)+(5/2x+40)=180
We move all terms to the left:
(3/2x+20)+(5/2x+40)-(180)=0
Domain of the equation: 2x+20)!=0
x∈R
Domain of the equation: 2x+40)!=0
x∈R
We get rid of parentheses
3/2x+5/2x+20+40-180=0
We multiply all the terms by the denominator
20*2x+40*2x-180*2x+3+5=0
We add all the numbers together, and all the variables
20*2x+40*2x-180*2x+8=0
Wy multiply elements
40x+80x-360x+8=0
We add all the numbers together, and all the variables
-240x+8=0
We move all terms containing x to the left, all other terms to the right
-240x=-8
x=-8/-240
x=1/30

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