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(3/2x+5)=(1/9x)
We move all terms to the left:
(3/2x+5)-((1/9x))=0
Domain of the equation: 2x+5)!=0
x∈R
Domain of the equation: 9x))!=0We add all the numbers together, and all the variables
x!=0/1
x!=0
x∈R
(3/2x+5)-((+1/9x))=0
We get rid of parentheses
3/2x-((+1/9x))+5=0
We calculate fractions
27x/18x^2+(-((+1*2x)/18x^2+5=0
We calculate fractions
We do not support expression: x^4
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