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(3/2x-3)=(2/x-5)
We move all terms to the left:
(3/2x-3)-((2/x-5))=0
Domain of the equation: 2x-3)!=0
x∈R
Domain of the equation: x-5))!=0We get rid of parentheses
x∈R
3/2x-((2/x-5))-3=0
We calculate fractions
3x/2x^2+(-((2*2x)/2x^2-3=0
We add all the numbers together, and all the variables
3x/2x^2+(-((+2*2x)/2x^2-3=0
We calculate fractions
We do not support expression: x^4
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