(3/2x-3)=(2x+5)

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Solution for (3/2x-3)=(2x+5) equation: 



(3/2x-3)=(2x+5)

We move all terms to the left:

(3/2x-3)-((2x+5))=0



Domain of the equation: 2x-3)!=0

x∈R



We get rid of parentheses

3/2x-((2x+5))-3=0

We multiply all the terms by the denominator


-(((2x+5)))*2x-3*2x+3=0

Wy multiply elements

-(((2x+5)))*2x-6x+3=0

We add all the numbers together, and all the variables

-6x-(((2x+5)))*2x+3=0

We move all terms containing x to the left, all other terms to the right

-6x-(((2x+5)))*2x=-3

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