(3/2y)-y=4+(1/2y)

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Solution for (3/2y)-y=4+(1/2y) equation: 


y in (-oo:+oo)

(3/2)*y-y = (1/2)*y+4 // - (1/2)*y+4

(3/2)*y-y-((1/2)*y)-4 = 0

(3/2)*y-y+(-1/2)*y-4 = 0

-4 = 0

y belongs to the empty set

y belongs to the empty set

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