(3/3k)-(4k/3k-12)

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Solution for (3/3k)-(4k/3k-12) equation: 


k in (-oo:+oo)

(3/3)*k-(((4*k)/3)*k)+12 = 0

(-4/3)*k^2+(3/3)*k+12 = 0

k-4/3*k^2+12 = 0

DELTA = 1^2-(-4/3*4*12)

DELTA = 65

DELTA > 0

k = (65^(1/2)-1)/(-4/3*2) or k = (-65^(1/2)-1)/(-4/3*2)

k = -3/8*(65^(1/2)-1) or k = 3/8*(65^(1/2)+1)

k in { -3/8*(65^(1/2)-1), 3/8*(65^(1/2)+1) }

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