(3/4)(12d-4)=33

Solution for (3/4)(12d-4)=33 equation:

(3/4)(12d-4)=33

We move all terms to the left:

(3/4)(12d-4)-(33)=0


Domain of the equation: 4)(12d-4)!=0

d∈R


We add all the numbers together, and all the variables

(+3/4)(12d-4)-33=0

We multiply parentheses ..

(+36d^2+3/4*-4)-33=0

We multiply all the terms by the denominator


(+36d^2+3-33*4*-4)=0

We get rid of parentheses

36d^2+3-4-33*4*=0

We add all the numbers together, and all the variables

36d^2=0

a = 36; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·36·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$d=\frac{-b}{2a}=\frac{0}{72}=0$