(3/4)(2x-3)=(6/5)(3x+1)

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Solution for (3/4)(2x-3)=(6/5)(3x+1) equation: 



(3/4)(2x-3)=(6/5)(3x+1)

We move all terms to the left:

(3/4)(2x-3)-((6/5)(3x+1))=0



Domain of the equation: 4)(2x-3)!=0

x∈R





Domain of the equation: 5)(3x+1))!=0

x∈R



We add all the numbers together, and all the variables

(+3/4)(2x-3)-((+6/5)(3x+1))=0

We multiply parentheses ..

(+6x^2+3/4*-3)-((+6/5)(3x+1))=0

We calculate fractions


((+6x^2+3*5)(3x+1)))/(-3)*5)(3x+1))+4*)+()/(-3)*5)(3x+1))+4*)=0

We calculate fractions


(((+6x^2+3*5)(3x+1)))*(-3)*5)(3x+1))+4*))/((*(-3)*5)3x)+(-3)*5)(3x+1))+4*)+()*()/((*(-3)*5)3x)=0

We can not solve this equation

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